/* Author: LukArToDo Created: 26.feb 2018 Bugs: bad spelling of English in comments ✍️😞 Description: The explanation of code Cube3D 🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸 ENTER A NUMBER (SIZE OF CUBE) ✔️press submit Note: for view on mobile device recommended size is between 2-12 🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸🔸 */ import java.util.Scanner; //import java.util.stream.IntStream; public class Cube3DExplanation{ public static void main(String...arg){ int n=new Scanner(System.in). nextInt(); /* IntStream.range(0,n+n/2+3).forEach (i->{if(n<2){System.out.print("Enter size of cube large than 1");System. exit(1);}System.out.printf("%"+(in+1?String.format ("%1s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/%"+(n*2-(n/2-(i-n- 2)))+"s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/","","","",""):""));}); */ /* The above code we split to the next 12 lines of code: line 1 IntStream.range(0,n+n/2+3).forEach (i->{ line 2 if(n<2){ line 3 System.out.print("Enter size of cube large than 1"); line 4 System. exit(1);} line 5 System.out.printf( line 6 "%"+(in+1?String. format("%1s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/%"+(n*2-(n/2-(i-n- 2)))+"s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/","","","","") */ /* Before explanation, see next draw: Input (size of cube) n=8 Note: -> height of front = n times '|' + horizontal lines -> width of front = 2*n + vertical lines -> height of top = width of side = n/2 + lines (horizontal/vertical) V1 V2 V3 V4 . . . . . . . . . +-------H1-------+ . . . . C1 . /| . /| . / | . / | . / | . / | ./ | ./ | +------H2--------+ . .|. . . . .C2 | | | | | | | | | | | | | +-----H3----|----+. . . . .C3 | / | / | / | / | / | / |/ |/ +------H4--------+. . . . . . . C4 space between V1 and V2 = n/2+2lines(V1+V2) space between V2 and V3 = n*2-n/2+2lines(V2+V3) space between V3 and V4 = n/2+2lines(V3+V4) space between V1 and V3 = n*2+2lines(V1+V3) We start count from 0, because that we need decrease points C2,C3,C4 for 1 : C1 -> i=0 C2 -> i=n/2+2 -1=n/2+2lines(H1+H2)-1 = n/2+1 C3 -> i=n+2 -1=n+2lines(H1+H3)-1=n+1 C4 -> i=n+n/2+3 -1=n+n/2+3lines (H1+H2+H4)-1=n+n/2+2 */ // Line 1: // IntStream.range(0,n+n/2+3).forEach (i->{ for(int i=0;ii=0, C4->n+n/2+2 if(i==0||i==n+n/2+2) { if(i==n+n/2+2) System.out.print(" "); System.out.print(String.format("+%0"+2*n+"d+",0).replace("0", "-")); /* What's happening here? "+0000000000000000+".replace("0","-") "+----------------+" for n=8 */ } // line 8: i==n/2+1?String.format("+%0"+ (2*n)+"d+%"+n/2+"s|",0,"").replace ("0","-"): // Now we draw line H2: // Note that H2 line is equal to line H1 or H4, // but after +-----------+ we have space(n/2) and character | if( i==n/2+1) System.out.print(String.format("+%0"+ (2*n)+"d+%"+n/2+"s|",0,"").replace ("0","-")); /* What's happening here? "+0000000000000000+ |".replace("0","-") "+----------------+ |" for n=8 */ // line 9: i / | Space between second | and third character / is 2*n-i+1 Space between third / and fourth | character is same as between first and second = i-1 (flag!=0) Resume, i=1 /| /| i=2 / | / | etc.. */ // line 10: in/2+1) System.out.print(String.format("%1s|%"+(n/2)+"s|%"+(2*n -n/2-1)+"s|%"+n/2+"s|","","","","")); // Note that we write "" as parameters because we wrote characters | inside expression: ""%1s|"... // line 11 i ==n+1?String.format("%1s|%"+n/2+"s+%0"+(2*n-n/2-1)+"d|%0"+n/2+"d+","","",0,0).replace("0","-"): // Here we draw line H3, i=n+1 /* Note that line H3 starts with character | then space (n/2) then line +-----| (2*n-n/2-1) then continue with ---+ (n/2): | +-----------|----+ for n=8 */ if(i==n+1) System.out.print(String.format("%1s|%"+n/2+"s+%0"+(2*n-n/2-1)+"d|%0"+n/2+"d+","","",0,0).replace("0","-")); /* What's happening here? for n=8: " | +00000000000|0000+".replace("0","-") we get: " | +-----------|----+" */ // line 12: i>n+1?String. format("%1s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/%"+(n*2-(n/2-(i-n- 2)))+"s|%"+((n/2-(i-n-1))==0?"":(n/2-(i-n-1)))+"s/","","","",""); // Here we edit lines between H3 and H4 (n+1n+1&&i

Explanation of code Cube3D