/** This program illustrates function overloading. It is possible to declare different functions using the same function identifier. These functions however have different signatures, typically different data types, or different number of arguments. The C++ compiler will select the version of the function that matches with the signature. */ /**Comments on the code can be found at the end of this program. * HAPPY LEARNING! */ /*************** CODE ************************/ #include using namespace std; int addNumbers(int); /* see 1 */ int addNumbers(int, int); double addNumbers(double, double); int main () { int xInt = 5; int yInt = 7; double xDouble = 3.3; double yDouble = 2.4; cout << "Calling the one integer version:" << endl; cout << "Sum is: " << addNumbers(xInt) << endl << endl; cout << "Calling the two integer version:" << endl; cout << "Sum is: " << addNumbers(xInt, yInt) << endl << endl; cout << "Calling the double version." << endl; cout << "Sum is: " << addNumbers(xDouble, yDouble) << endl; return 0; } int addNumbers(int first) { cout << "Inside the one integer version." << endl; return first + first; } int addNumbers(int first, int second) { cout << "Inside the two integer version." << endl; return first + second; } double addNumbers(double first, double second) { cout << "Inside the double version." << endl; return first + second; } /*************** COMMENTS ********************/ /* 1 There are 3 functions declared here, all using the same identifier 'addNumbers'. They all have different number or different type of arguments. When addNumbers() is called the compiler will choose among the thre based on the parameters. */ /* 2 */

Function Overloading Example - Explained