// by bell /* Challenge by Elisabeth Kelly based on Punnett Squares[Challenge] challenge by jianmin chen With this inheritance model a parent with genotype AB can only pass on an A allele or a B allele. Therefore it should not be possible for their children to have genotype OO/phenotype O (because they need one O allele from each parent). But, there are many other factors that determine a person’s overall blood type. One is a gene called the H-antigen. If someone is homozygous-recessive (hh) for the H-antigen the normal ABO phenotype is masked. Instead an O phenotype is expressed regardless of the ABO genotype. This is known as the Bombay phenoype - More info at: https://www2.palomar.edu/anthro/blood/Bombay_pheno.htm Given Phenotypes: Monica, mother, type B; Rick,father, type AB; Timmy,child,type O Possible Genotypes: Monica-BBHh or BOHh Rick-ABHh Timmy-ABhh or BBhh or AOhh or BOhh But phenotype is O blood type! Refer to Jianmin Chen's challenge for more info on basic inheritance. */ #include #include #include #include using namespace std; int main() { vector traits={"A", "show the phenotype ","B","show phenotype O no matter what"}; // Genetic traits vector nickname={"blood group","phenotype"}; string Rick="ABHh"; vector Monica={"BBHh","BOHh"}; string f=Rick,m=""; int n=0,l,ll; bool recessive; srand(time(NULL)); cout<<"This program calculates the possible genetics of the O-typed Timmy"<180)recessive=true; ll++; if(!(ll%2)){cout<<'|'<

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