/* -------------------------------------------- ############################################ -------------------------------------------- INPUTS ARE: 1st: SIZE of each 3D shape 2nd: HORIZONTAL repetition of the pattern 3rd: VERTICAL repetition of the pattern (e.g. 6 1 9) IF YOU ARE RUNNING THE CODE FROM A PHONE I SUGGEST TO ENTER NO INPUT But feel free to experiment. If you do so, don't forget to rotate the screen! -------------------------------------------- ############################################ -------------------------------------------- */ #include void printBlock( const int b, const int xR ); void printchar( const int n ); int size = 6; int row; // current row being printed within a block int main() { int xRepeat = 1; int yRepeat = 9; int block; // block of characters to be printed // there are only two different blocks scanf( "%d %d %d", &size, &xRepeat, &yRepeat ); for(block = 0; block < yRepeat; ++block) { for( row = 0; row < size; ++row ) { printBlock( block, xRepeat ); } } return 0; } // end main void printBlock( const int b, const int xR ) { int i; if( b % 2 == 0 ) { for( i = 0; i < size-row; ++i ) { printf(" "); } for( i = 0; i < xR; ++i ) { printchar( 0 ); printchar( 1 ); printchar( 2 ); printchar( 3 ); } } else { for( i = 0; i <= row; ++i ) { printf(" "); } for( i =0; i < xR; ++i ) { printchar( 2 ); printchar( 3 ); printchar( 0 ); printchar( 1 ); } } puts(""); } // end printBlock void printchar( const int n ) { int i; static const char *characters[4] = {"//", "¶L", "\\\\", "• "}; if( n == 0 ) { for( i = 0; i < row; ++i) printf("%s", characters[0]); } else if ( n == 2 ) { for( i = 1; i < size - row; ++i) printf("%s", characters[2]); } else { for( i = 0; i < size; ++i) printf("%s", characters[n]); } } // end printchar

3D Pattern