/* Created : 25/07/2018; Last updated : 13/06/2019 ; by mark 🇺🇬 This interconverts between Fahrenheit scale and Celsius scale. your comments are highly welcome. HOW to use: enter value 1 or 2 followed by the temperature to be converted. where; enter 1: to convert from °F to °C; or 2: to convert from °C to °F; then leave space (or press 'enter') followed by the 'value to convert.' THEN SUBMIT THANKS */ #include using namespace std; float convertC (float); float convertF (float); int main() { float tempFer, tempCel; cout << "Let\'s interconvert between the Fahrenheit and the Celsius temperature scales \n"; cout << "Choose 1 or 2 : \n"; cout << "\n 1. from °F to °C \n"; cout << "\n 2. from °C to °F \n"; int convChoice; cout << "your choice please : \n"; cin >> convChoice ; if (convChoice){ cout << "\nYou chose:\t" << convChoice << endl; } else { cout << "\nYou chose:\t None "<< endl; } cout << "\n\n\n"; switch(convChoice ){ case 1: cout << "please enter your temperature (°F):\t\n"; cin >> tempFer ; tempCel = convertC (tempFer); cout << "\nYou entered:\t" << tempFer << "\n\n \n \tYour answer is : " << tempCel << "°C" << endl; break; case 2: cout << "Please enter your temperature (°C):\t\n"; cin >> tempCel; tempFer = convertF (tempCel); cout << "\nYou entered:\t" << tempCel << "\n\n\n\tThe answer is " << tempFer <<"°F\n"; break; default: cout << "please check your input, it should be 1 or 2\n thanks\n"; } cout << "\n\n\n Thanks very much, \n I\'ll appreciate the upvote and/or comment."; return 0; } float convertC (float tempFer){ float tempCel; //tempCel = ((tempFer -32) *5)/9; tempCel = (tempFer - 32)/1.8; return tempCel; } float convertF (float tempCel){ float tempFer; //tempFer = 32 + ((9*tempCel)/5); tempFer = (tempCel * 1.8) + 32; return tempFer; }

temperature conversion c++