#include using namespace std; int flip(int); int main() { int n,b = 0,ii = 0; cin >> n; // so you need to input one positive odd number N, and it will return an N by N matrix, //where 1 is in the center, zeros in its neighborhood, ones in zeros' outer neighborhoods and so on... // for example inputing 5 will yeild such a 5 by 5 matrix: //11111 //10001 //10101 //10001 //11111 if(n < 0) { n*=-1; cout << "your input is negative, so we will take '" << n << "' as an input" << endl << endl; } if(n % 2 == 0) { n++; cout << "your input is even, so we will take '" << n << "' as an input" << endl << endl; } int arr[n][n]; if((n + 3) % 4 == 0) { b++; } for(int i = 0;i < n;i++) { ii = i; if (i > (-1 + n / 2)) { ii = n - i - 1; } for(int j = 0;j < ii;j++) { arr[i][j] = b; b = flip(b); cout << arr[i][j]; } for(int j = 0;j < (n - 2*ii);j++) { arr[i][j] = b; cout << arr[i][j]; } for(int j = 0;j < ii;j++) { b = flip(b); arr[i][j] = b; cout << arr[i][j]; } cout << endl; } cout << endl << "a " << n << " by " << n << " matrix, with 1 at the center, and alternating values" << endl; return 0; } int flip(int i) { i--; i*=-1; return i; }

Alternating matrix