##### Code made by Nevfy: 2018-04-19 ##### # Challenge: Gravitational Numbers # Solution: Optimal ''' Gravitational Numbers. Numbers have mass and gravitate towards one another. Choosing 2 random numbers in the range of (0-9) compare them side by side above and below as follows. (<<) = Mass to left is greater. (>>) = Mass to Right is greater. (><) = Mass is equal both sides. (0) = Blackhole all surrounding mass gravitates towards this. Example for the input 3x3: 5 >> 6 >> 0 v v v v v ^ 7 >> 9 >> 0 ^ ^ ^ ^ ^ ^ 1 >< 1 >> 8 ''' import numpy as np # returns gravitational relation between 2 numbers in a row def get_hor_gravity(num1,num2): if num1 > num2: return '<<' elif num1 < num2: return '>>' else: return '><' def gravity_matrix(r,c): # generate matrix of given shape with random numbers from 1 to 10 m = np.random.randint(1,11,(r,c)) # A TRICK: # to keep functions which defines gravitational relation simple # I generate numbers from 1 to 10, where 10 means 0. # In a such way only 3 if-else statements required instead of 6 # To print out 0 instead of 10 I print a number%10 # printing out for i in range(r): # check one line outline = "" for j in range(c-1): relation = get_hor_gravity(m[i,j],m[i,j+1]) outline += "{} {} ".format(m[i,j]%10,relation) print(outline+"{}".format(m[i,c-1]%10)) # compare with next line if i < r-1: outline1,outline2 = "","" for j in range(c): outline1 += "{} ".format('^' if m[i,j] > m[i+1,j] else 'v') outline2 += "{} ".format('v' if m[i,j] < m[i+1,j] else '^') print(outline1) print(outline2) ## main block r=int(input()) # number of rows c=int(input()) # number of columns gravity_matrix(r,c) ## test block #gravity_matrix(3,2) #gravity_matrix(7,5)

2018-04-19_Gravitational-numbers_optimal_python