/*code by Ogbuagu beloved francis beginer in c++ but tried to create this*/ /*thanks to the c++ wizard Jamie who inspires me without knowing*/ /*input a number an it's binary will be displayed*/ /* if there's a way for me to loop or fewer code for this teach me please.. enter positive numbers from 1 to 1023*/ /* if you like this code upvote please*/ /*thanks to Danijel Ivanovic his binary challange made me taught of this*/ #include using namespace std; int main() { int x; cin>>x; int a=x/2; int b=a/2; int c=b/2; int d=c/2; int e=d/2; int f=e/2; int g=f/2; int h=g/2; int i=h/2; int j=i/2; int p=x%2; int q=a%2; int r=b%2; int s=c%2; int t=d%2; int u=e%2; int v=f%2; int w=g%2; int y=h%2; int z=i%2; /*if statment is to ensure that only the binary is displayed no additional 0000*/ /* this is how the below code works: in binary operation from base 10 to 2, 1 has value of 1(note: not the actuall value but the length of value) 2 and 3 has value 2(length value ) 4 to 7 has value 3(length value) 8 to 15 has value 4(length value) 16 to 31 has value 5.. notice that for each binary length value to add 1 the base 10 length value muliplies by 2(base value*=2)...*/ if(x==1){ cout<=2 && x<=3){ cout<=4 &&x<=7) { cout<=8 && x<=15) { cout<=16 && x<=31){ cout<=32 && x<=63){ cout<=64 && x<=127){ cout<=128 && x<=255){ cout<=256 && x<=511){ cout<=512 && x<=1023){ cout<

[challenge] base 10 to Binary converter