/* Spyral NxN matrix v1.1 Sololearn by Dinmukhamed Mailibay Hello world! This program prompts for an integer input and outputs the square matrix outputing numbers in spiral form Please Thumb up if you like it and write all your recomendations in comment v 1.1 added exception handling */ #include #include using namespace std; template string ToStr (T SomeInt) //declaring the method for converting ints to strings { ostringstream obj; // obj << SomeInt; return obj.str(); } int main() { int n = 0; try { cin>>n; if ((n<1) || (n>10) || (ToStr(n).size()>2)||(ToStr(n) =="")) { throw 0; } } catch (...) { cout<<"Wrong value input. Input an integer from 1 to 10"; n = 0; } int sq = n*n, ord[32768] = {}, s = 1, m = 0, c1 = 1; while (s < n) // ordering the numbers into an array { for (int i = 0; i <= n - s; i++) { ord[m++] = c1++; } // moving horizontally (left to right) at the top m--; for (int i = 0; i < n - s; i++) { m += n; ord[m] = c1; c1++; } // moving vertically (up to down) at the right for (int i = 0; i < n - s; i++) { m--; ord[m] = c1; c1++; } // moving horizontally (right to left) at the bottom for (int i = 0; i < n - s - 1; i++) { m -= n; ord[m] = c1; c1++; } //moving vertically (down to up) at the left m++; s+=2; //'reducing' the size of the matrix going inside by one layer if ((n % 2 != 0) || (s < n + 1)) // stop the cycle if n is even at the last step { ord[m] = c1; } } cout<<"\n"; for (int j = 0; j < sq; j++) { cout << ord[j]; for (int i = 0; i < ToStr(sq).size() - ToStr(ord[j]).size(); i++) { cout << " "; } //the for loop outputs 'missing' spaces depending on the length of each number if ((j + 1) % n != 0) //outputing space when moving horizontally { cout << " "; } else { cout << "\n"; } } return 0; } //your input should be an integer between 1 and 10

Spiral NxN matrix