#include int N=0; unsigned int a[100][7]= {0}; void adj(int,int); // add and help in adjusting the information of an employee void print(); // to print all employee in magic way int search(int,int);// to look for someone void print1(int); // to print the information of specific employee void change(int); // to change the information of specific employee void del(int); // to delete a specific employee int max(); // to get the maximum salary void pmax(); // to print the employee of biggest salary int sum(); void ps(int); // just for print a specific number of spaces for print() function int in(); // to have a safe input //made by legends int main () { int t=0;//this variable is for choice and get the initial information from the user; printf("what should I do?\n"); printf("1 to add employee\n2 to print all employees\n3 to search \n4 to delete an employee's information\n5 to print a specific employee\n6 to change the employee's information\n7 to show the maximum salary\n8to show who has the maximum salary\n9 to calculate the sum of salaries\nAny key except digits to exit\n"); while(scanf("%d",&t))//scanf() return 0 when the user did not enter a number so it will break the loop when any key except digits is entered { switch(t) { case 1: adj(N,0); N++; break; case 2: print(); break; case 3: printf("enter the number of the employee\n"); t=in(); if(search(0,t)<0) printf("not "); printf("exists"); break; case 4: printf("enter the number of the employee\n"); t=in(); del(t); break; case 5: printf("enter the number of the employee\n"); t=in(); print1(t); break; case 6: printf("enter the number of the employee"); t=in(); change(t); break; case 7: printf("the maximum salary is %d",max()); break; case 8: pmax(); break; case 9: printf("total salaries of all employees is %d",sum()); break; default: printf("error");// I did not argue the char case of input here because it will print error whatever the case } printf("\nwhat should I do?\n"); printf("1 to add employee\n2 to print all employees\n3 to search \n4 to delete an employee's information\n5 to print a specific employee\n6 to change the employee's information\n7 to show the maximum salary\n8 to show who has the maximum salary\n9 to calculate the sum of salaries\nany key to exit\n"); } printf("enjoy!!"); return 0; } void adj(int n,int i) { // this array helps in printing const char pr[6][30]= {"number of employee","number of working days","","","salary","monthly bonus"}; // int i; for(i; i<6; i++) { if(i==2||i==3) continue; printf("enter the %s:\n",pr[i]); a[n][i]=in(); if(a[n][i]==0) { printf("error input please try again\n"); i--; } if(i==0&&search(0,a[n][i])>=0)//the second condition is in order to not add two employees with the same id number { printf("this number is already entered ... please try again\n"); i--; } else if(i==1&&a[n][1]>30)//this condition to prevent add days more than month { printf("wow how he did it he worked more than day per day .... try again\n"); i=0;// back to 0 then i++ => i=1 add working days *_- } } a[n][2]=30-a[n][1]; if(a[n][2]>2) { a[n][3]+=a[n][2]-2;//when vacations are more than 2 will add the rest to absence days then leave two days in vacations a[n][2]=2; } // counting total salary // total = salart(1-absence/30)+bonus a[n][6]=(a[n][1]>a[n][3])?a[n][4]*(1-(float)a[n][3]/30)+a[n][5] : 0;//when working day less than absence the employee does not worth his salary and I will kick this cocky lazy later } void print () { int i,j;//this array to make printing easier const char pr[7][20]= {"| Number ", " Working Days ", "Vacations Days", "Absence Days ", " Salary ", "Monthly Bonus ", " Total salary "}; for(i=0 ; i<7 ; i++) { printf("%s|",pr[i]); } printf("\n"); for (i=0; imax) max=a[i][6]; return max; } void pmax() { printf("this employee has the biggest total salary: %d",a[search(6,max())][0]);// search return the index of employee *_- } int sum() { int i,sum=0; for(i=0; i='0'&&x[i]<='9'; i++) { in*=10; in+=x[i]-'0'; } if(i==k)// that mean the input of the user is an integer return in; return 0;//when the user enter a character not a digit will return 0 }