/* 🍇🍇CHALLENGE🍉🍉. IT'S ALL ABOUT BASES. Objective: 👉 Write aprogram, that convert a number in a certain base to another base FORMAT : 👉Your program should take three input : ☝The number to be converted ✌ The base of the number to be converted 👌The base to which you wish your number to be converted to. Example : number : 2E base : 16 tobase: 5 Output =141 ---- number: 3245 base: 6 tobase: 9 Output = 1022 LIMITATIONS : 👉Don't use module/built function that converts, example bin(),hex() Here's mine: https://code.sololearn.com/cRFGPQn2VEts/?ref=app The first 10 correct codes will reposted by me and get best answer mark. DO IT */ #include #include using namespace std; class Base { private: int base; string figures=""; long unsigned int value=0; long unsigned int Notation(int pow) // create a power of "base" number { long unsigned int ret=1; for(int i=0 ; i9 && i<36)figures += 'A'+i-10; //if (i>35)throw .........??......TODO } } public: Base(int C_base):base(C_base) { build(base); cout<<"New obj base("<base); ret.value = this->value+obj.value; return ret; } // * * * OPERATOR '+=' '-=' overloading void operator+=(Base &obj) { value+=obj.value; } void operator+=(int obj) { value+=obj; } void operator+=(string obj) { //stuff here................TODO } void operator-=(Base &obj) { value-=obj.value; } // * * * UTILITIES int getInt() { return value ; } int getBase() { return base; } void showfigures() { cout<0 ; tempValue/=obj.base){ number.insert(0,1,obj.figures[tempValue%obj.base]); } out<>x; cout<>basex; cout<>basey; cout< A.convertto(basey)... the new value is.. "< B+=A.. Now B is.. "< C=A+B... C is.. "<

CHALLENGE base converter