""" In this simple game you try to score a free throw. The code shows the path of the ball as it flies through the air and bounces of the walls. How many tries before you can score? input: speed (in km/h) angle (in degrees) example input: 28 60 """ # constants: mass(m),gravity(g) # parameters: acceleration(a,ax,ay), velocity(v,vx,vy), position(x:horizontally,y:vertically), angle(alpha),time(t),time-step(dt) # forces: gravitational (fz), total forces(fres,fresx,fresy) from math import sqrt,sin,cos,pi curve = [] score = 0 for y in range(40): curve.append([]) for x in range(40): curve[y].append(" ") def ring(x,y,str=curve): for i in range(5): curve[39-y][x+i] = "=" for i in range(4): curve[40-y][x+i] = "#" curve[41-y][x+i] = "#" def field(str=curve): for i in range(40): curve[0][i]="_" curve[39][i]="_" curve[i][39]="|" field() # constant values try: input = input().split() v = float(input[0])/3.6 alpha = float(input[1])*pi/180 except: v = 26/3.6 alpha = 70*pi/180 t = 0 dt = 0.1/v x = 0.1 y = 0.5 g = 9.8 yb = 3.05 xb = 4.225 wb = 0.45 symbol = "+" vx = v*cos(alpha) vy = v*sin(alpha) ay = -g while t<200*dt: # acceleration with Newton's second law. # calculation of positions x and y x = x + vx*dt vy = vy + ay*dt y = y + vy*dt curve[39-int(10*y)][int(10*x)]=symbol if 3.63.8: vy = -vy if y<0.1: if score == 0: print("You missed the basket, try again!") break if x<0.1 or x>3.9: vx = -vx # next time step t = t + dt ring(34,20) for i in range(40): print("".join(curve[i]))

bball physics