/* The Fiscal Code Note 1 : Write a Program in any Language Note 2 : If you have any doubt ask in comment Note 3 : Read problem carefuly. Each person in Italy has an unique identifying ID code issued by the national tax office after the birth registration: the Fiscal Code (Codice Fiscale). Given an object containing the personal data of a person (name, surname, gender and date of birth) return the 11 code characters as a string following these steps: Generate 3 capital letters from the surname, if it has: At least 3 consonants then the first three consonants are used. (Newman -> NWM). Less than 3 consonants then vowels will replace missing characters in the same order they appear (Fox -> FXO | Hope -> HPO). Less than three letters then "X" will take the third slot after the consonant and the vowel (Yu -> YUX). Generate 3 capital letters from the name, if it has: Exactly 3 consonants then consonants are used in the order they appear (Matt -> MTT). More than 3 consonants then first, third and fourth consonant are used (Samantha -> SNT | Thomas -> TMS). Less than 3 consonants then vowels will replace missing characters in the same order they appear (Bob -> BBO | Paula -> PLA). Less than three letters then "X" will take the the third slot after the consonant and the vowel (Al -> LAX). Generate 2 numbers, 1 letter and 2 numbers from date of birth and gender: Take the last two digits of the year of birth (1985 -> 85). Generate a letter corresponding to the month of birth (January -> A | December -> T) using the table for conversion given below. For males take the day of birth adding one zero at the start if is less than 10 (any 9th day -> 09 | any 20th day -> 20). For females take the day of birth and sum 40 to it (any 9th day -> 49 | any 20th day -> 60). Example: fiscalCode({ name: "Matt", surname: "Edabit", gender: "M", dob: "1/1/1900" }) ➞ "DBTMTT00A01" fiscalCode({ name: "Helen", surname: "Yu", gender: "F", dob: "1/12/1950" }) ➞ "YUXHLN50T41" fiscalCode({ name: "Mickey", surname: "Mouse", gender: "M", dob: "16/1/1928" }) ➞ "MSOMKY28A16" Notes: Code letters must be uppercase. Date of birth is given in D/M/YYYY format. The conversion table for months is given below. Letter Month Letter Month A January P September B February R October C March L July D April M August E May S November H June T December */ #include #include #include #include #include #include using namespace std; using UD = vector; auto Rearrange(string src) { stable_partition(src.begin(), src.end(),[](char& ch){ return !strchr("AEIOU",(ch=toupper(ch))); }); return src.size() < 2 ? src+"XX" : src+'X'; } auto Parsedate(string date) { stringstream ss(date), ss1; string tmp; while(getline(ss,tmp,'/')) { ss1 << setw(2) << setfill('0') << tmp; } return ss1.str(); } auto ParseUsrdata(string inp) { stringstream ss(inp); string tmp; UD usrd; while(getline(ss,tmp,',')) usrd.emplace_back(tmp); usrd[3] = Parsedate(usrd[3]); return usrd; } auto Calfiscalcode(string usrd) { UD ud = ParseUsrdata(usrd); // rearrange name and surname ud[0] = Rearrange(ud[0]); ud[1] = Rearrange(ud[1]); stringstream ss; // 3 chars from surname ss << ud[1].substr(0,3); // 3 chars from name ss << ((ud[0].size() > 4 && !strchr("AEIOU",ud[0][3])) ? ud[0][0]+ud[0].substr(2,2): ud[0].substr(0,3)); // 2 chars from year of birth ss << ud[3].substr(ud[3].size()-2); // 1 char from month of birth ss << "ABCDEHLMPRST"[stoi(ud[3].substr(2,2))-1]; // 2 char from date of birth depending on gender string sdate = ud[3].substr(0,2); ss << (ud[2] == "M" ? sdate : to_string(stoi(sdate)+40)); return ss.str(); } int main(int argc, char *argv[]) { for(auto&& usrd : { "M,Edabit,M,1/1/1900", "Helen,Yu,F,1/12/1950", "Mickey,Mouse,M,16/1/1928", "Samantha,Fox,F,9/5/2005", "Bob,Newman,M,23/10/2016" }) cout << "User details: " << usrd << '\n' << "Fiscal Code: " << Calfiscalcode(usrd) << "\n\n"; }

[Challenge] Fiscal Code.cpp