// Created by Miss Rashmi Lulla #include using namespace std; void newAdvisors(string *advisorname, string *username, string *password); void loggin(string *username, string *password); // NOTE: you should declare the functions outside of main usually at the top // of the file or in a separate header file, and then call them without // specifying the return type /*Encasing other functions into the main function*/ // NOTE: you should include a return type when you define main int main() { // the arrays were local to newAdvisors, so you couldn't access them from loggin // By putting them in main, they will exist while the program is running string advisorname[10] = {"", "", "", "", "", "", "", "", "", ""}; string username[10] = {"", "", "", "", "", "", "", "", "", ""}; string password[10] = {"", "", "", "", "", "", "", "", "", ""}; // you can pass the arrays in as paramters to access them inside functions newAdvisors(advisorname, username, password); loggin(username, password); return 0; } /*Configuring userids*/ // changed return type to void because 0 can't be returned as a string void newAdvisors(string *advisorname, string *username, string *password) { // these parameters are equivalent to "string advisorname[]" or "string advisorname[10]" int i = 0; for (i = 0; i < 10; i++) { cout << "Enter your name:"; cin >> advisorname[i]; cout << endl; cout << "Enter an alphanumeric 6 character username to login for " << advisorname[i] << ":"; // NOTE: you had an extra cout here, you only need to specify it once cin >> username[i]; cout << endl; cout << "Note: Password has to be min 6 characters & max 8 characters.\n"; cout << "There has to be atleast 1 uppercase & 1 number.\n"; cout << "Enter a Password for " << advisorname[i] << ":"; string s; cin >> s; password[i] = s; cout << endl; /*Informing how many users are required*/ if (i < 10) { int n = i + 1; cout << n << "userids configured." << (10-n) << "advisors userids not configured.\n"; // NOTE: there was a missing << at the beginning, so the compiler didn't know what to do with n } else { // NOTE: this never gets called, maybe take a look at the condition in the if statement? cout << "All 10 userids configured.\n"; } } } /* Advisors logging in. Headcount required is 5. Authenticating username and password*/ void loggin(string *username, string *password) { cout << "Headcount requirement is 5\n"; string u, p; int headcount = 0; // NOTE: the "while" comes at the end in a do-while loop do { cout << "username: "; cin >> u; cout << "\n Password: "; cin >> p; cout << endl; // NOTE: you didn't declare a type for i originally, always remember to define variables before assigning to them int i = 0; // NOTE: same while loop syntax as mentioned above do { // NOTE: username and password were defined in a separate function. This is why we need to pass them as parameters if (u == username[i] && p == password[i]) { cout << "access accepted" << endl; headcount = headcount +1; cout << headcount << "advisors logged in. \n"; i++; } // NOTE: if the 'if' statement doesn't happen, then the program will loop forever becase i never changes } while (i < 10); } while (headcount < 5); }

c++ compiling errors 2