/** This program illustrates the use of pointers in an array. We also show a simple example of pointer arithmetic. */ /** More comments can be found at the end of the code. /** HAPPY LEARNING! */ /*************** CODE ************************/ #include using namespace std; int main() { const int arraySize = 5; int myArray[arraySize] = {2, 4, 7, 9, 1}; int *p = myArray; /* see 1 */ cout << "Index \tValue \tAddress" << endl << endl; for (int i=0; i< arraySize; i++){ /* see 2 */ cout << i << "\t"; cout << myArray[i] << "\t"; cout << &myArray[i] << "\t" << endl; } cout << endl; cout << "p is pointing at address: " << p << endl; cout << "The value of *p is: " << *p << endl << endl; cout << "Moving p to the next memory address." << endl; p = p+1; /* see 3 */ cout << "p is pointing at address: " << p << endl; cout << "The value of *p is: " << *p << endl; return 0; } /*************** COMMENTS ********************/ /* 1. p is a pointer to myArray. p holds the address of the first element in myArray. It is equivalent to declare int *p = &myArray[0]. */ /* 2. Here we print the content of the array. Notice that all elements in an array are stored in consecutive memory locations 4 bytes apart. Address values are given using Hexadecimal numbers. */ /* 3. When we add 1 to p the pointer will move to the next element in the array. Since the size of an integer is 4 bytes then 4 will be added to the current value of p. */

C++ Arrays and Pointers