/* Monday Blue 💙 Challenge Series #3 Let's have some fun! A roller coaster number can be obtained by populating all the numbers between 2 adjacent digits in range [0123456789]. 💼 TASK Write a program to accept an integer and produce the output in the following pattern (e.g. 10250):- [1 ⬇] [0 ⬆] 1 [2 ⬆] 3 4 [5 ⬇] 4 3 2 1 [0] 🔧 TEST CASE ☑ 1 ▶ 1 ☑ 123 ▶ 123 ☑ 11111 ▶ 11111 ☑ 1233 ▶ 1233 ☑ 00123 ▶ 00123 ☑ 191 ▶ 12345678987654321 ☑ 00179 ▶ 00123456789 ☑ 12375 ▶ 123456765 ☑ 15552 ▶ 1234555432 ☑ 17900 ▶ 1234567898765432100 ☑ 030201 ▶ 012321012101 ☑ 152857 ▶ 1234543234567876567 Happy Coding!!! 😁💻 */ #include #include using namespace std; int main() { string input; // The input string is to receive the string of digits. int incr = 0; //incr is to set a number to increment through the input string's character's later. // We define this string outside of the for loop, so that we can print the // final character of the string once the upcoming outer for loop terminates. //Receive the input. cout << "Input a string of numbers: "; cin >> input; // (Output formatting purposes) cout << endl << "Output: "; //This for loop is to increment through each character in the string. We set // the stopping point at the character before the end of the input string so // so that we can compare the current character against the next character. for(incr = 0; incr < (input.size() - 1); incr++){ // If any given character in the input is anything other than a digit, the // program terminates. if(input[incr] > '9' || input[incr] < '0'){ cout << "Input included a character other than a digit. Terminating."; return 0; } //Otherwise, we convert each character in the input to an integer and store it // in currNum and the following digit in nextNum. else{ int currNum = input[incr] - '0'; int nextNum = input[incr + 1] - '0'; //If currNum is larger than the next number, we increment through until we // reach nextNum printing each digit along the way. if(currNum < nextNum){ for(int i = currNum; i < nextNum; i++){ cout << i; } } //If currNum is smaller than nextNum, we decrement through until we // reach nextNum printing each digit along the way. else if(currNum > nextNum){ for(int i = currNum; i > nextNum; i--){ cout << i; } } //If currNum and nextNum are equal, than we simply print currNum. else{ cout << currNum; } } } //Because we printed every number (except the last) based on how it compared with // the next in the input string, we still must print the last number out to // finish outputting the entire sequence. We use incr for easy access to the final // element here. cout << input[incr]; return 0; }

&#127942; [M&#128153; Challenge] Roller Coaster Number &#127906;

🏆 [M💙 Challenge] Roller Coaster Number 🎢