/*[CHALLENGE]🏆 Print the following series 📑 Description: Print numbers in alternating order. You should take a number as input : >> 5 And your output should be : >> [0,5,1,4,2,3] Let's take another input as : >> 10 And, your output should be: >> [0,10,1,9,2,8,3,7,4,6,5,5] ✨ Hint: Every two consecutive numbers add up to give the input 🔖 Note: Your output list should have even number of terms Best of luck 👍 # Happy coding*/ #include using namespace std; int main() { int x; int i; int array[100]; cout << "Enter a value: "; cin >> x; cout << x << endl; cin.clear(); if(x%2!=0) { int slot1 = 0; int slot2 = x; //Filling array with values for(i=0; i> [0 1] --> 2 itens 2 >> [0 2 1 1] --> 4 itens 3 >> [0 3 1 2] --> 4 itens 4 >> [0 4 1 3 2 2] --> 6 itens 5 >> [0 5 1 4 2 3] --> 6 itens 6 >> [0 6 1 5 2 4 3 3] --> 8 itens 7 >> [0 7 1 6 2 5 3 4] --> 8 itens 8 >> [0 8 1 7 2 6 3 5 4 4] --> 10 itens 9 >> [0 9 1 8 2 7 3 6 4 5] --> 10 itens 10 >> [0 10 1 9 2 8 3 7 4 6 5 5] --> 12 itens 11 >> [0 11 1 10 2 9 3 8 4 7 5 6] -> 12 itens ... and so on Now, let's call the input x. For each time x is odd, the number of itens is equal to x+1 (the statement in the for loops inside the if(x%2!=0)) For each time x is even, the number of itens is equal to x+2 (the statement in the for loops inside the else) The loops were just a way to iterate the indexes of the array and to print the values in the end. The first loop fills the even indexes (0,2,4,6...) of the array with values starting from 0 and incrementing 1 by 1 (0,1,2,3...). The second loop fills the odd indexes (1,3,5,7...) of the array with values starting from the input (x) and decrementing 1 by 1 (x, x-1, x-2, x-3...). The third loop just outputs all the contents inserted on the array. I hope it helps everyone. Enjoy it and happy coding from Brazil. Jonathan Álex :) */

Challenge - Print the Following Series