/* Write a C++ program that reads a set of names and a date in a specific format (given below) for each name and store it in a structure array. The name list will be terminated with the string end. Names will not exceed 30 characters. Then a set of query strings will be provided from the std. input related with the person name and the date. Your program needs to provide correct information about the stored dates. The query can ask the year, the month or the day of the date data using the encoding letters: Y, M, D respectively. Please look at the sample input/output files to understand the convention. The name queries will also be end with the string end. INPUT: MARY 02/03/1998 PATRICIA 07/10/2004 LINDA 24/04/1998 BARBARA 15/06/2001 ELIZABETH 30/12/1989 JENNIFER 20/11/1976 MARIA 19/05/1919 SUSAN 22/01/2010 end PATRICIA D BARBARA M SUSAN Y MARY M ELIZABETH D SUSAN D PATRICIA M end OUTPUT: PATRICIA 7 BARBARA 6 SUSAN 2010 MARY 3 ELIZABETH 30 SUSAN 22 PATRICIA 10 */ #include #include using namespace std; struct sDate{ string day,month, year; }; struct Person{ string name; sDate date; }; sDate getDate(string str ){ sDate tempDate; tempDate.day=str.substr(0,2); tempDate.month=str.substr(3,2) ; tempDate.year=str.substr(6,4); return tempDate; } string leadingZero(string str){ if(str[0]=='0') return str.substr(1, str.length()); return str; } string getInput( Person person, char ch){ switch(ch){ case 'D': return leadingZero(person.date.day); break; case 'M': return leadingZero(person.date.month); break; case 'Y': return leadingZero(person.date.year); break; } return ""; } int main(){ Person people[505]; string tempName, tempDate; int i=0,len; char tempChar; cin>>tempName; while(tempName != "end"){ cin>>tempDate; people[i].name=tempName; people[i].date=getDate(tempDate); i++; cin>>tempName; } len=i; cin>>tempName; while(tempName != "end"){ cin>>tempChar; for(int k=0; k< len; k++){ if( people[k].name == tempName ){ cout<< people[k].name << " " << getInput( people[k], tempChar )<>tempName; } }

lab2(15.03.2019)